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Factor out the common factor of 3a. 9a^5/4-6a^9/2
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\[3a(\frac{3a^4}{4}-\frac{2a^8}{2})\]
Is that what you want?
\[3a^5(\frac{3}{4}-\frac{2a^4}{2})\]
\[=3a^5(\frac{3}{4}-a^4)\]
are the powers 5/4 and 9/2?
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yes they are the powers
\[3^{5/4}(3-2a^{13/4})\]
sorry,\[3a^{5/4}(3-2a^{13/4})\]
bad day
Are you factoring out 3a or 3a^5/4?
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If you are factoring 3a then the answer would be 3a(3a^1/4 - 2a^7/2)
THanks beens.....I got another one if you dont mind
no prob
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