3x^2 – 5x – 2 Factor problem and show the work.
you'll have to use delta and all that stuff
\[\Delta= b^2 - 4ac\] a=3 b= -5 c = -2 \[\Delta = (-5)^2 - 4(3)(-2) = 49\] so : \[ x = -b \pm \sqrt{\Delta}/2a\] substitute delta and do the calculation :) give it a try.
what will your answer be?
Your answer should be:\[x1 = 2 \] and \[x2 = -1/3\] did you get that?
nice sstarica you are smart
thank you ^_^
If the directions said to factor, then you can't use the quadtratic formula. The answer would be (3x + 1)(x - 2) there is no solution if you don't have an = sign to begin with.
u also can use the calculator ..its very easy and efficient..
but you've got to learn the way too :) never trust techonology in the end, they fail you.
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