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solve sq.rt. 3y+2=4
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y= 2/3
the sq root of that is .8164965
y=14/3
\[\sqrt{3y+2}=4\] is this the question?
yes
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first, squared both side. then, make it in term of ay=b, a,b is are arbitrary. finally, make it y=b/a
sq.both sides sq.3y+2 = sq.4
i am confused i have no examples in my books
You should always check you answers when you raise both sides to an even power though
so y= 2/3
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yes
sorry.my bad.the answer is 2/3
okay
3y + 2 = 4 sq 3y + 2 = 16 3y = 16-2 3y=14 y=14/3 y=4 and 2/3
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