slope intercept form of equation of line through points. through: (-5, -3), slope = 2/5
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myininaya (myininaya):
equation of a line can be written in the form (x-x_1)m=y_1-y
myininaya (myininaya):
oops (x-x_1)m=y-y_1
myininaya (myininaya):
we know m=2/5 and we know a point (x_1,y_1)=(-5,-3)
myininaya (myininaya):
(x-(-5))2/5=(y-(-3))
myininaya (myininaya):
(x+5)2/5=y+3
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myininaya (myininaya):
2x/5+5*2/5=y+3
myininaya (myininaya):
2x/5+2=y+3
myininaya (myininaya):
subtract 3 on both sides to put it in the form y=mx+b
OpenStudy (anonymous):
okay
myininaya (myininaya):
y=2x/5-1
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OpenStudy (anonymous):
i just dont understand how -5 and -3 turned into -1
myininaya (myininaya):
if we subtract 3 on both sides 2-3=-1
OpenStudy (anonymous):
of mx + b?
myininaya (myininaya):
no you were asking how i got -1 right?
OpenStudy (anonymous):
yea
i understand the y= 2/5 x just not how u got -1 from (-5, -3)
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myininaya (myininaya):
do you understand where I got 2x/5+2=y+3
OpenStudy (anonymous):
not the 2nd 2 and 3
myininaya (myininaya):
the point slope formula is (x-x_1)m=y-y_1 where in this case a line on this point is (x_1,y_1)=(-5,-3) and m=2/5 since that is the slope of this line
myininaya (myininaya):
so we have (x-(-5))*2/5=y-(-3)
myininaya (myininaya):
(x+5)*2/5=y+3
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myininaya (myininaya):
Use distributive property we have 2x/5+5*2/5=y+3
myininaya (myininaya):
we want to put this in y=mx+b form which is the slope intercept form
myininaya (myininaya):
Since the above equation has y by itself we need to solve for y by subtracting 3 on both sides
myininaya (myininaya):
2x/5+2-3=y
myininaya (myininaya):
y=2x/5+2-3
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myininaya (myininaya):
y=2x/5-1
OpenStudy (anonymous):
o okay now i understand thank u
myininaya (myininaya):
cool!
OpenStudy (amistre64):
the slope-intercept equation is:
y = mx + b
You know the slope, and they give you (x=-5,y=-3); so lets plug and play...
-3 = (2/5)(-5) +b ; solve for "b".
-3 = -2 + b
-1 = b
throw away your (-5,-3) and use the equation as it:
y = (2/5)x - 1