Question

solve. round to 4th decimals, separate answer with commas if necessary.
(x^2)(2x)-(2^x)=0

Answer 1

Are you sure you have this entered correctly?

Answer 2

sorry its \[x ^{2}2^{x}-2^{x}=0\]

Answer 3

I would factor this.. common factor is 2^x.
So you would have 2^x(x^2 - 1) = 0
Then you have the difference of two squares so you have
2^x(x + 1)(x - 1) = 0
So every where there is an "x" there is an answer.
So x + 1 would give you an answer of -1
... x - 1 would give you an answer of 1

When does 2^x = 0?

Answer 4

x would be 0, so -1 and 1 would work