Mathematics
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OpenStudy (anonymous):
solve symbolically
3 sq x-3+27=51
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OpenStudy (anonymous):
(x-3) is in a radical?
myininaya (myininaya):
I think thats what he means
OpenStudy (anonymous):
it is the radical
OpenStudy (anonymous):
\[3\sqrt{x-3}+27=51\]
OpenStudy (anonymous):
move the 27 over, then divide by 3 on both sides
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OpenStudy (anonymous):
51+27 then divide by 3
OpenStudy (anonymous):
no, subtract 27 from both sides
OpenStudy (anonymous):
u get 24, then divide by 3 to get rid of the number infront of the radical.. so u get 8
OpenStudy (anonymous):
yeah that is what i have
OpenStudy (anonymous):
so what then do I put it \[3\sqrt{8-3?}\]
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OpenStudy (anonymous):
27 cancels on left side
OpenStudy (anonymous):
\[3\sqrt{x-3}=24\]
OpenStudy (anonymous):
\[\sqrt{x-3}=24/3\]
OpenStudy (anonymous):
\[\sqrt{x-3}=8\]
OpenStudy (anonymous):
that is the answer? symbolically
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OpenStudy (anonymous):
r u trying to find x? is that what u mean by symbolically
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
all it says is solve the equation symbolically
OpenStudy (anonymous):
\[(\sqrt{x-3})^2= (8)^2\]
OpenStudy (anonymous):
x-3=64, add 3 to the other side, nd u get 67
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OpenStudy (anonymous):
okay I got that i see where you get it
OpenStudy (anonymous):
that is what x is equal to, but i dont know what it means by solve symbolically..i hope it helped a bit
OpenStudy (anonymous):
thank you I will see when I do my test and submit it