Question

when finding a perimeter of a rectangle. if one side is the square root of 27 and the other is square root of 108. what would the exact perimeter be?

Answer 1

Sqrt(27) + sqrt(108) + sqrt(27) + sqrt(108)
Then you need to simplify each radical
Do you know who to do that?
sqrt(27) = 2sqrt(3)
What is sqrt(108) =

Answer 2

i show its a decimal is that right?

Answer 3

No.. you can't do it that way. If they want "exact" Have you been working on radicals and simplifying them?

Answer 4

Do you know how to do a factor tree?

Answer 5

yeah we have to find the lcd
or gcf

Answer 6

27 = 3 * 3 * 3
108 = 2 * 54
= 2 * 2 * 27
= 2 * 2 * 3 * 9
= 2 * 2 * 3 * 3 * 3
So 108= 2 * 2 * 3 * 3 *3
Doyou understand this?

Answer 7

yeah

Answer 8

OK the way you simplify a radical is - circle groups of two that are alike.
FOr example. 27 = 3 * 3 * 3 you would circle the first two 3's and they go outside the sign with the uncircled 3 left underneath.
sqrt(27) = 3sqrt(3)

108 = 2 * 2 * 3 * 3 * 3 you would circle the 2's and the 3's and there would be one 3 left over. You multiply things that come out, and multiply things that are left underneath.
sqrt(108) = 6sqrt(3)

So 3sqrt(3) + 6sqrt(3) + 3 sqrt(3) + 6sqrt(3) = 18sqrt(3)
That is your answer...

Answer 9

wow i really like that break down thank you

Answer 10

You are welcome