how do you find ALL the values between 0 and 2pi for cos(theta)=-0.0623??

Question

anonymous · Answer

Not sure I understand the question, but this is what I think:

Take the inverse cosine==> cos^-1(-0.0623)  then add 90deg or pi/2(if your problem is in radians) until you go all the way around the unit circle.  So if you problem is in radians you should get 1.633,3.203,4.774, 6.345

amistre64 · Answer

you take the cosine inverse to determine the angle.   Which will spit out an angle in the top half of the circle; swing down to get the other one...

anonymous · Answer

when i take the inverse cos, i get 93.... which is not between 0 and 2pi

anonymous · Answer

your calculator is in degrees, need to change it to radians

anonymous · Answer

yah.. duh! thanks!

anonymous · Answer

Oh, amistre64 is right, you should add 180deg (pi) not pi/2...sorry just saw that, you should get 1.633 and 4.774 only, my bad

anonymous · Answer

ya. thanks