2/(a+3) - (a^2+3a-10)/(a^3+5a^2+6a)=(a-4)/(a^2+3a) Solve for a. Please explaiiin to me how this is -6?

Question

anonymous · Answer

PLEASE, someone answer this question, outcastlilgurl has been waiting here for like an hour

anonymous · Answer

outcast, just wait a few minutes, be patient, sstarica always helps, she is like an angel

anonymous · Answer

alright, first you need to set them to the same denominator, you'll get :$$= [2a(a+2) - (a+5)(a-2) - (a-4)] / a(a+3)(a+2) $$$$= (2a^2 + 4a - a^2 - 3a + 10 - a^2 + 2a - 8)/a(a+3)(a+2)$$$$= 3(a+3)/a(a+2)(a+3) = 3/a(a+2)$$
that's what I got ._.

anonymous · Answer

lol, andy

anonymous · Answer

are you sure it must be = -6?

anonymous · Answer

he got tired of waiting so he went downtown to get a coke

anonymous · Answer

lol

anonymous · Answer

or , you move the 2nd portion to the other side and simplify to get the same denom. then cross multiply and you'll get in the end:

5a^2 + 12a - 9 = 0

then a = 3/5 and a = -3

radar · Answer

I get -6

radar · Answer

Which proved to be wrong........too many numbers Ilost ttrack.

anonymous · Answer

geez well then the math answer key must be wrong...

anonymous · Answer

and I'm a girl XD