Question

(2x+4y)/(x^2-y^2) times (x+y)/(x^2+4xy+4y^2) just checking is this the right answer? 2/(x62-y^2) ?

Answer 1

sorry I meant 2/(x^2-y^2)

Answer 2

no

Answer 3

ok could you explain what I got wrong?

Answer 4

\[2/(x^2 +xy-2y^2)\]

Answer 5

I need to see your solution in order to find your mistake/ It's just regular stuff

Answer 6

Here's how I factored it out: \[2(x+2y)/(x+y)(x-y) \times (x+y)/(x+2y)(x+2y)\]

Answer 7

then, I removed (x+y) from denominator and numerator, and then (x+2y) to simplify

Answer 8

leaving me with 2/(x-y)(x+2y)

Answer 9

then I multiplied the fractions

Answer 10

ohhh wait now I see what I got wrong...I forgot about the 2 factor in 2y...but thanks anyway... :)

Answer 11

u got mistake at the very end? welcome

Answer 12

\[(x-y)(x+2y)=x^2+xy-2y^2\]

Answer 13

(x^2-y^2) is equal to (x+y)(x-y), not
(x-y)(x+2y)

Answer 14

sorry, i had to sign up to reply so it took super long lol

Answer 15

its ok lol thanks for trying! haha