I am trying to evaluate the intergral [(ax^3-bx^7)/x^(-1/2)] and I'm not given an interval. I'm asuming it is a through b. understand the process of integrals, I'm just getting caught up with the algebra......

Question

I am trying to evaluate the intergral [(ax^3-bx^7)/x^(-1/2)] and I'm not given an interval.  I'm asuming it is a through b.  understand the process of integrals, I'm just getting caught up with the algebra......

anonymous · Answer

when no limit of integration is given, that is called an indefinite integral

anonymous · Answer

what does it mean to have to evaluate the intergral ????????

anonymous · Answer

So simplify (ax^3-bx^7)/x^(-1/2) to becomes

ax^(7/2) - bx^(15/2)

Integrate it will give

(2/9)ax^(9/2) - (2/17)bx^(17/2) + C, where C is a constant

anonymous · Answer

i got a^6 - b ^-14 ,, i simpliefied, istha evaluating the intergral,,, or what is the intergral??

anonymous · Answer

Sorry, I had to go to class.  Indefinite Integral, yes you are right sklee.  Thank you sklee and MiL3ARN3R.  I am getting a couple different answers here.  I will be back online later.  Thanks again.