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OpenStudy (anonymous):
22r^3s^2 over 11r^2s^-3
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OpenStudy (amistre64):
22 r^3 s^2
--- --- ----- subtract bottom exponents from top exponents
11 r^2 s^-3
2 r^(3-2) s^(2--3) = 2 r s^5
OpenStudy (amistre64):
2 negatives makes a positive, I dont care where your at :)
OpenStudy (anonymous):
alright lol im really really bad at algebra
OpenStudy (anonymous):
I got (2r) (1/2^-5)
OpenStudy (amistre64):
mit: then you musta did something wrong :)
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OpenStudy (anonymous):
i just divie the s over its 2s which gave me 1/2 ^5 ,do you know where I went rong
OpenStudy (amistre64):
cant say fer sure, but I got an inkling of an idea...
its the "s" variables that are catching you up right?
OpenStudy (amistre64):
what happens when we do this:
2-(-3) = ??
OpenStudy (anonymous):
my bad , now I know my abc's ,, i was looking at the s^3 as 2s^3 because of 11r^2 ,
OpenStudy (amistre64):
and I think youre seeing the problem wrong; it aint 2s that we are working with..
yeah, you figured that out :)
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OpenStudy (anonymous):
im knew here
OpenStudy (amistre64):
new or old; at least your here :)
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