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is there a way to prove that cos(pi/3)=1/2
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Let V be the image point corresponding with the angle pi/3 on the unit circle and let E the intersection point of that circle with the positive X-axis. The triangle 'OVE' is equilateral. sin^2 (pi/3) = sqrt( 1 - cos^2 (pi/3)) = sqrt(3)/2 So, sin(pi/3) = sqrt(3)/2 and cos(pi/3) = 1/2.
if you write the cosine in terms of Euler's formula and expands in power series of the \[e^{i \theta} \] and \[e^{-i \theta} \] , you will get cos( pi/3)=1/2.
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|dw:1336890915598:dw| \[\cos (\frac{\pi}{3}) = \frac{1}{2}\] hehe :P
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