Question

From a boat on the lake, the angle of elevation to the top of a cliff is 12°50'. If the base of the cliff is 1366 feet from the boat, how high is the cliff (to the nearest foot)?

Answer 1

1366(tan(12'50'')) '=degree and ''=minute for this one :)

Answer 2

okay :)

Answer 3

(79/6) degrees ??

Answer 4

319.554 is what the calculator spits out :) that is if 79/6 is a good number.

12 and 50/60 = 12 5/6 = (72+5)/6 = 77/6

gotta recalc it :)

Answer 5

:)

Answer 6

311.183 lets try that one on fer size :)

Answer 7

i got 311.09

Answer 8

close enough....311 is prolly the answer then

Answer 9

:) thank you can you help me with my next one

Answer 10

maybe :) is it an easy one?

Answer 11

its kind of the same as this

Answer 12

lets here it

Answer 13

From a boat on the river below a dam, the angle of elevation to the top of the dam is 30°25'. If the dam is 1065 feet above the level of the river, how far is the boat from the base of the dam (to the nearest foot)?

Answer 14

these are basically tan problems

Answer 15

oh ok

Answer 16

[30(60)+5]/60 is going to be the number for my degrees..

tan(n) = 1065/x

x = 1065/tan(n)...

Answer 17

1838.453 double check that...

Answer 18

1838.453 its what I get :)

Answer 19

1813 ft?

Answer 20

nope... messed up someplace... my number for degrees specifically..

Answer 21

[30(60)+ 25] /60

Answer 22

recalculating....

Answer 23

1814.03 is what i get with the right numbers :)

Answer 24

i did it that way and got 1838.7

Answer 25

wow lol

Answer 26

I added a "5" it aint 5/60 minutes... its 25/60 minutes

so I had to get the right number for degrees :)

Answer 27

oh ok

Answer 28

im sure its 1814, or close to that :)

Answer 29

thank you :)