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logx9 = -2 . what's the value of x?
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the log argument is 9x or x^9??
And what's the base of the logarithm?
the base is x
Ohhhh. Much easier, then. So, x^(-2) = 9 which means that x = 9^(1/2) or -9^(1/2) = 1/3 or -1/3.
Right!
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no no no
Should the negative term not be in there? I wasn't completely positive. :P
(Pun.)
not there... the correct way write is 9=x^-2 9=1/x^2 x^2=1/9 x=+1/3 or x=-1/3
Yes, I just skipped a step. Sorry :P
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