Question

f(x) = 2x2 - 12x + 2
[0, 8]
find the absolute max and absolute min of f on the given interval

Answer 1

Take the derivative.=> 4x -12
set it equal to 0 to find critical points. 0 = 4x -12
=> x = 3

Answer 2

f'(x)=4x-12---> x= 3
f(0)=2
f(8)=2(64)-12(8)+2=....

Answer 3

Try x=3, and our boundary points 0 , and 8 into the original equation. and figure out which gives the biggest value and which gives the smallest value.