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Mathematics 21 Online
OpenStudy (anonymous):

Is the answer E ? http://img17.imageshack.us/img17/8670/andysnap009.png

OpenStudy (anonymous):

If your answer's E, when you sub. x=b in, you don't get zero. You should get zero because it's a root of the polynomial.

OpenStudy (anonymous):

but isn't (x+2)^2 .. -2 to the left..?

OpenStudy (anonymous):

b is in the positive side of the number line.

OpenStudy (anonymous):

Two other things to consider - the shape of the graph is such that the coefficient of x^3 is negative, and there's a double root at a since it just touches the axis and there are no complex roots (if there were, it would look different).

OpenStudy (anonymous):

Those three pieces of information should kill four of the five possibilities.

OpenStudy (anonymous):

but b is (x-b)^2

OpenStudy (anonymous):

shouldnt that be to the right

OpenStudy (anonymous):

sorry (x-a)^2

OpenStudy (anonymous):

or do we count the negative outside the bracket as well?

OpenStudy (anonymous):

The negative outside the bracket is allowing you to have a negative coefficient on x^3, which is what you need.

OpenStudy (anonymous):

Do you want me to go through them?

OpenStudy (anonymous):

yes please

OpenStudy (anonymous):

Well, A is out because the coefficient of x^3 will be positive.

OpenStudy (anonymous):

C, D, E are out because you have a double root at a, which means the factor containing a should be raised to the power of 2.

OpenStudy (anonymous):

Leaves B

OpenStudy (anonymous):

ohhh I get it now :) Thanks for your time :)

OpenStudy (anonymous):

No probs.

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