Question

Solve for W: 2w^3-w^2+6w-3=0

Answer 1

factor by grouping and you'll get ^_^:\[= w^2(2w-1) + 3(2w-1) = (2w-1)(w^2+3)\]

Answer 2

Thanks!

Answer 3

np ^_^

Answer 4

you can also use horner's method of factoring polynomial

Answer 5

not to be a stickler in the mud; but there is no "W" in the problem :)

Answer 6

lol, he meant w :)

Answer 7

meant, schmeant.... lol

Answer 8

lol, alright ^_^

Answer 9

Not to be a stickler, but the phrase is, "a stick in the mud"

Answer 10

\[\log_{17} 17^{y}\]

Answer 11

Remember that

\[k = log_{b}x \iff b^k = x\]

Answer 12

so let
\[ k = log_{17} 17^y \rightarrow 17^? = 17^y\]

Answer 13

canadian eh....

Answer 14

\[\log_{17} 17^{y}\]

Answer 15

... are you repeating the question for any particular reason?

Answer 16

Nah, i got it. typo. Thanks anyway