Question

Note that in an isosceles triangle, two angles have the same measure and the sum of all three angle measures is 180 degrees. Set up and equation and solve:

Determine the measure (in degrees) of the third angle in an isosceles triangle, if the third angle is 10 more than one-half of either of the equal measure angles.

Answer 1

since two angles are equal let's say they both equal x. ok?
so angle 1 =x and angle 2 =x since angle 1 and 2 are the same.

not it says the third angle is 10 more than one half of either one.
so third angle = 10 + (x/2)

so now you can add all the three angles up and make them equal to 180 and you will find your answer.

so x + x + 10 + (x/2) = 2x + 10 + (x/2) = 5x/2 + 10 = 180
so 5x/2 = 170
5x = 340
x = 340/5
x = 68

Answer 2

so angle 1 = 68
angle 2 = 68
angle 3 = 10+(68/2) = 10 + 34 = 44

and if you add all those up they will equal to 180