Question

2log(base8)4-(1/3)log(base8)8=x

Answer 1

What number are both 8 and 4 a power of?

Answer 2

log(base8)4^2-log(base8)8^(1/3)=log(base8)[4^2/8^(1/3)]

Answer 3

Are you good now smurfy?

Answer 4

sorry for late response i didnt see my new notifications! um i get what myininaya did but what would you do after that?

Answer 5

simplify!

Answer 6

=log(base8)[16/2] i will let you do the last step

Answer 7

or last two steps

Answer 8

so x=1 correct?

Answer 9

:) YES!

Answer 10

whoo thanks so much!

Answer 11

think you could help me with one more?

Answer 12

ok

Answer 13

2. Jamal has a game with 2 groups of tiles. The first group of 26 tiles is labeled with all the letter of the alphabet, The second group of 10 tiles is #0-9. If Jamal draws one letter tile and one # tile at the random, what is the probability that he will draw a letter in his name and an odd number?
A. (1/13) B. (5/52) C. (1/4) D. (7/26)

Answer 14

i got 17/26 :(

Answer 15

let me think about it

Answer 16

ok and ya all the answers tht i was getting werent on there either :P

Answer 17

i suck at probability, but give me a few and I will think

Answer 18

I get A

Answer 19

could u plz explain it to me?

Answer 20

did you P(AUB)=P(A)+P(B)-P(A and B)

Answer 21

No, I used the probability of two independent events is their product.

Answer 22

So how many ways can Jamal draw a letter that is in his name?

Answer 23

jaml

Answer 24

its independent events because A has nothing to do with B good thinking bond

Answer 25

right, so 4/26

Answer 26

someone explain how rhey got A!

Answer 27

dont worry about A

Answer 28

Now, how about the probability of pulling an odd tile?

Answer 29

1/10

Answer 30

how many odd numbers are between 0 and 9?

Answer 31

ohhhh ODD 5/10!

Answer 32

ok so since they are independent events you multiply the (5/10)(4/26)

Answer 33

ok see ididnt get it bc ithought it said 1/10 not 5/10 imissedthe odd part lol thanks!!

Answer 34

lol

Answer 35

one more q! 3^2x=7^(x-1)

Answer 36

Eeek, that doesn't look good...

Answer 37

hahaha

Answer 38

q! is read as q factorial?

Answer 39

jk lol i know you mean another question!

Answer 40

take the natural log of both sides

Answer 41

you mean get the decimal form of both? if so thats what i did but for some reason i came out with a negative # :(

Answer 42

ln3^(2x)=ln7^(x-1)

Answer 43

2xln3=(x-1)ln7

Answer 44

2xln3=xln7-ln7

Answer 45

2xln3-xln7=-ln7

Answer 46

x(2ln3-ln7)=-ln7

Answer 47

x=-ln7/(2ln3-ln7)

Answer 48

x=-ln7/(ln8-ln7)

Answer 49

x=-ln7/(ln(8/7))

Answer 50

ok i see so b4 i write the work does the answer comeout positive?

Answer 51

you have a negative in front of it so its negative

Answer 52

ok so were allowed to have a negative as the answer?

Answer 53

ln(negative)=does not exist ln(0) does not exist -lna exist if a>0

Answer 54

so the answer is?

Answer 55

the answer to?

Answer 56

are we still talking about the previous solution?

Answer 57

ya the one with the negative

Answer 58

so you are saying its not a solution? why do you say that?

Answer 59

what? i just want to know what you got for the answer lol

Answer 60

we can check it to see

Answer 61

youre confusing me

Answer 62

you want to know if it is a solution. if you ever have doubt about something, check it

Answer 63

no i dont want to know if it is a solution i just want to know the answer lol so would the answer be "no solution"?

Answer 64

give me just sec and i will check k??

Answer 65

it is a solution if i did each step correctly

Answer 66

so the final answer is....?

Answer 67

you know like x=?

Answer 68

i can scroll back up and look just sec

Answer 69

it says x=-ln(7)/(ln(8/7))

Answer 70

so if you put that in your calc what is the number? (sorry i dont have a good calc with me)

Answer 71

> evalf(solve(3^(2*x) = 7^(x-1)));
-7.742930467
>

Answer 72

ok thanks!

Answer 73

smurfy it is not easy to check the solution, but it is the solution because exponential functions are continuous everywhere

Answer 74

but logarithmic functions are not continuous everywhere log(baseb)x=lnx/lnb so whenever the base is 1 or negative or 0 and whenever x is negative or 0, the the function is undefined