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3sqrt{32} - 4sqrt{63}
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32=2^5 so sqrt{32} = 2^(5/2) 63=9*7= 7*3^2 so sqrt{63} = 3*sqrt{7}
wait...what?
32=2^5?
\[2^{5}=32\]
okay, but i'm trying to get the square roots to be the same so I can subtract the terms.
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I think.
3*sqrt{32} = 3*2^(5/2) =12sqrt{2} 4*sqrt{63} = 12sqrt{7}
okay thank you...
u r welcome.
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