Question

inscribed in an equalateral riangle is a circle. the height of the circle is 12 times the square root of 3. what is the circumference?

Answer 1

okay, let's write the given:\[h = 12\sqrt{?}\]

the height is actually the diameter of the circle so :

\[D = h = 12\sqrt{3}\]

So you can find R :

\[R = D/2 = 12\sqrt{3}/2 = 6\sqrt{3}\]

substitute R in the general equation of the circumference which is:
\[C = 2\pi r =12\sqrt{3}\pi\]
Correct me if I'm wrong ^_^

Answer 2

h= 12sqrt(3) * my bad :)

Answer 3

the circumference of the circle is = \[2\prod_{}^{}r\] =2 * pi * (\[12\sqrt{3} / 2\]

Answer 4

= 2 * pi * 6 sqrt(3)

Answer 5

^_^

Answer 6

correct answer ???

Answer 7

did u get it?

Answer 8

lol that's what I got, he hopefully got it now ^_^