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How do I solve this for x?? 3/(1-3x) + 5/(2-x) + (9-2x)/(3x^2 - 7x + 2) = 0
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First step is to find a common denominator (LCD, or least common denominator). Then multiply every term by the LCD.
as (1-3x)*(2-x)=3x^2-7x+2 , you should multiple 3x^2-7x+2 to each side then: 3*(2-x)+5*(1-3x)+9-2x=0 and then x=1.
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