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OCW Scholar - Single Variable Calculus
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in the problem f(x)=x^n where n=1,2,3.... what is (d/dx)x^n? you get ((x+delta(x))^n -x^n)/(delta(x)) where does -x^n come from if the difference quotient is: (f(x-delta(x))-f(x))/(delta(x)) ? thanks
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\[((x_0+\Delta x )^{n}-x^{n}_0)/\Delta x\]
The difference quotient is \[(f(x+\Delta x) - f(x))/\Delta x\]so given that f(x)=x^n, the -x^n value in your equation if the substitution of f(x) into the difference quotient.
thanks Xavier
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