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8+2/3(2n-9)=10
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Just to be clear, is your equation,\[8+\frac{2}{3(2n-9)}=10\]?
or
\[8+\frac{2}{3}(2n-9)=10\]?
Your aim is to isolate the n. What you need to do is 'unwrap' it. Showing you is probably easiest. Subtract 8 from both sides first to get\[\frac{2}{3}(2n-9)=2\]
We need to get rid of the fraction next. So multiply both sides by 3\[2(2n-9)=6\]
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Now we need to divide both sides by 2 to get\[2n-9=3\]
Now add 9 to both sides,\[2n=12\]
and finally, divide both sides by 2 to get\[n=6\]
Happy with that?
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