trying to solve for x. In a polygon the four angles are: (20-5x)+(2x+80)+(x2-4)+(x2+5). [where x2 is x squared].

Question

trying to solve for x.  In a polygon the four angles are: (20-5x)+(2x+80)+(x2-4)+(x2+5).  [where x2 is x squared].

anonymous · Answer

polygons with four sides have angles that add to 360 degrees

(20 - 5x) + (2x + 80) + (x^2 - 4) + (x^2 + 5) = 360
Add like terms
2x^2 - 3x + 101 = 360
Set the one side = to 0
2x^2 - 3x - 259 = 0
Do you know how to solve this?

anonymous · Answer

Are you sure your problem is accurate... It doesn't come out to be a "nice" number and I would think it would at this level.

anonymous · Answer

Yes, I checked the angles are accurate.  I am not clear about how you got 2x^2 - 3x - 259 = 0.  I thought it would be 2x^2+2x-264=0.  Any suggestions?