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Mathematics 22 Online
OpenStudy (anonymous):

what is the exact value of sin15 ? (using the subtraction formula)

OpenStudy (anonymous):

help!

OpenStudy (anonymous):

I don't know about the subtraction formula (never heard of it) but the half angle identity should work

OpenStudy (nikvist):

\[\sin^215=\frac{1-\cos 30}{2}=\frac{1-\sqrt{3}/2}{2}=\frac{2-\sqrt{3}}{4}\] \[\sin15=\frac{\sqrt{2-\sqrt{3}}}{2}\]

OpenStudy (anonymous):

That's it right there^

OpenStudy (anonymous):

I think the subtraction formula would mean that you would take two sin values that you know and use them to get sin 15 Sin 45 - Sin 30 I will get back with the formula

OpenStudy (anonymous):

OK here is the formula sin(A−B) = sin A cos B − cos A sin B

OpenStudy (anonymous):

im required to use this formula sin(s-t)= sin(s)cos(t) - cos(s)sin(t)

OpenStudy (anonymous):

Sin(45-30) = sin45*cos30 - cos45*sin30

OpenStudy (anonymous):

Sin 45 = sqrt2/2 cos 45 = sqrt2/2 sin 30 = 1/2 cos 30 = sqrt3/2

OpenStudy (anonymous):

The difference identity! Yup that works better!

OpenStudy (anonymous):

sqrt2/2*sqrt3/2 - sqrt2/2*1/2 sqrt6/2 - sqrt2/2 (sqrt6 - sqrt2) /2

OpenStudy (anonymous):

would it be over 4 after multiplying

OpenStudy (anonymous):

OOPS - yes

OpenStudy (anonymous):

thanks so much!

OpenStudy (anonymous):

U R Welcome

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