Mathematics
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OpenStudy (anonymous):
what is the exact value of tan15
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OpenStudy (anonymous):
tan(A−B) = (tan A − tan B) / (1 + tan A tan B)
OpenStudy (anonymous):
Tan(45 - 15)
OpenStudy (anonymous):
OOPS Tan(45 - 30)
OpenStudy (anonymous):
(tan 45 - tan 30)/(1 + tan45*tan30)
OpenStudy (anonymous):
Tan 45 = 1
tan 30 = sqrt3/3
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OpenStudy (anonymous):
(1 - sqrt3/3)(1 + sqrt3/3)
OpenStudy (anonymous):
how do you simplify that? the answer is supposed to be 2 - sqrt3
OpenStudy (anonymous):
Just a minute... I don't get that answer.. Let me go back thru my math
OpenStudy (anonymous):
i got up to where you got before too
OpenStudy (anonymous):
OK
(1 = sqrt3/3) / (1 + sqrt3/3)
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OpenStudy (anonymous):
Now you multiply by the conjugate which is (1 - sqrt3/3)/(1-sqrt3/3)
OpenStudy (anonymous):
(1 - sqrt3/3)(1 - sqrt3/3)
---------------------
(1 + sqrt3/3)(1 - sqrt3/3)
OpenStudy (anonymous):
1 - sqrt3/3 - sqrt3/3 + 3/9
------------------------
1 - 3/9
OpenStudy (anonymous):
1 - 2sqrt3/3 + 1/3
-----------------
2/3
OpenStudy (anonymous):
4/3 - 2sqrt3/3
-------------
2/3
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OpenStudy (anonymous):
(4 - 2sqrt3)/3 divided by 2/3
(4 - 2sqrt3)/3 times 3/2
OpenStudy (anonymous):
The threes would cancel
(4 - 2sqrt3)/2
OpenStudy (anonymous):
divide the 2 into each term
2 - sqrt3
OpenStudy (anonymous):
how do you find the conjugate again?
OpenStudy (anonymous):
The conjugate is basically the denominator but take the opposite sign
ex. denominator = 1 - sqrt5 conjugate 1+sqrt5/1+sqrt5
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OpenStudy (anonymous):
perfect, thanks!
OpenStudy (anonymous):
UR welcome