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Can this be solved?: (x^2 - Radical x)(2x- Radical x) so far I have 2x^3..
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yes... (x^2 - sqrt(x)) (2x - sqrt(x)) x^2(2x) - x^2(sqrt(x)) - sqrt(x)(2x) + sqrt(x)sqrt(x) 2x^3 -x^2sqrt(x) - 2x sqrt(x) + x Now, what does it mean to be solved??
I meant to be put into a simplified form such as what you wrote. Would this be considered the same answer?: 2x^3 - (x^2 + 2x) Radical x + x
hmm...... the easiest thing to do is to redistribute that rad(x) back in.... 2x^3 -x^2 rad(x) -2x rad(x) + x So yes....
Awesome. thank you so much!
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