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f'(x) = 2x - e^x = 0
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what do you want to find?
to solve for x?
i want to find x
I believe this is just part of the whole question, what actually are you working on?
Finding the absolute maximum and minimum values of f(x) = 2x - e^x on [0,1]. i'm stuck
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ok, good, then the information given above is not correct f(x) = 2x - e^x f'(x) = 2 - e^x
You can solve your f'(x) = 0 easily now
i see that e^x should be 2 but wat about x
e^x = 2 Take log on both sides: x = log(2), log = natural logarithm
ok
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I believe you know how to determine the absolute extrema
plugging that into the fucntion with the endpoint values and determining the max and min
very good, yup
thx for ur help
you're welcome
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