find the axis of symmetry and vertex of
x squared + 5x- 12

Question

find the axis of symmetry and vertex of
 x squared + 5x- 12

anonymous · Answer

for any parabola in the form:
$$f(x) = ax ^{2} = bx + c$$

you can find the axis of symmetry using using the equation below:
$$x = -b \div 2a$$

that then gives you your x coordinate which is the axis of symmetry (note that this is also the x coordinate for the vertex, by substituting the x value back in to the original equation you will get the y coordinate of the vertex).

therefore the above equation will equal:
$$x=-5\div2(12)$$ $$= -5/24$$

anonymous · Answer

f(x)=ax2+bx+c***
fixes the + sign to a = sign which is an error in the first equation