Question

find the axis of symmetry and vertex of
x squared + 5x- 12

Answer 1

for any parabola in the form:
\[f(x) = ax ^{2} = bx + c\]

you can find the axis of symmetry using using the equation below:
\[x = -b \div 2a\]

that then gives you your x coordinate which is the axis of symmetry (note that this is also the x coordinate for the vertex, by substituting the x value back in to the original equation you will get the y coordinate of the vertex).

therefore the above equation will equal:
\[x=-5\div2(12)\] \[= -5/24\]

Answer 2

f(x)=ax2+bx+c***
fixes the + sign to a = sign which is an error in the first equation