Question

ln3x-3lnx+ln3y

Answer 1

I'm not too sure about what you exactly need. Are you meant to just simplify?

Answer 2

\[\ln 3x -3 \ln x + \ln 3y =\ln 3 + \ln x - 2\ln x + \ln 3 + \ln y\]

Answer 3

\[= \log \frac{9y}{x^2}\]

Answer 4

\[=2\ln 3 -2\ln x +\ln y\]

Answer 5

Mistake in the first expression I typed: -2lnx should be -3ln x as in the question.

Answer 6

\[=\ln 3^2-\ln x^2+\ln y= \ln \frac{3^2}{x^2}+\ln y = \ln \frac{3^2y}{x^2}=\ln \frac{9y}{x^2}\]