Question

need help with factoring following question.
2a^3b^3 + 10ab =

Answer 1

you can take 2ab as a common factor so you'll have:

\[2ab(a^2b^2 + 5) = 0\]

^_^

Answer 2

Can you please explain. I am a sub in AEP and cannot help in this subject. This young man does not understand algebra either. He has 6 questions, would you be willing to walk him through these?

Answer 3

What does it mean to "factor" an equation?

Answer 4

alright, when it comes to factoring, it's more like to write down the expression in its most simplified form.

In other words, we take out what's common from both sides.

What common variables/numbers do we have here? :)

Answer 5

we have in the first part:

\[2a^3b^3\]

and in the second part :

10 ab and 10 can be written as ( 2 x 5)ab

so what do we have in common in both parts? what can we pull out? ^_^

Answer 6

from both parts*

Answer 7

what do we have in common flash? :)

Answer 8

it means to "un"multiply really.

the factors of 16 are all the numbers that multiply together to get 16.

1*16
2*8
4*4

the factors of 16 are: 1,2,4,8, and 16.

Answer 9

lol, I wanted to explain it in a much easier way amistre :)

Answer 10

sstar, youre doing great :)

Answer 11

thank you ^_^, flash did you get it now?

Answer 12

he says he still does not understand.

Answer 13

it would help to know what it is that he doesnt understand, ther are alot of underpinning concepts involved.

Answer 14

i dont understand how to work it

Answer 15

okay , look at this:

2(a)(a)(a)(b)(b)(b) + (2)(5)(a)(b)

to factor, we need to pull out what we have in common, in this case we have 2, a and b common in both sides so we pull out :

2ab

then we're left with :
(a)(a)(b)(b) + (5)

so we can write this down as :

2ab( a^2b^2 + 5 ) ^_^

clear?

Answer 16

i gotta head to class, have fun sstar :)

Answer 17

lol , I will GL amister ^_^

Answer 18

o ok i get it

Answer 19

yay ^_^, so if you want to check your work, you can use the distributive property and it'll get you back to the original form :)

Answer 20

so would a^2b^2+5 be the anwser

Answer 21

no you forgot the 2ab :)

so the answer now is :
\[2ab(a^2b^2 + 5)\]

remember, we pulled out 2ab :) so it'll stay out , clear? ^_^

Answer 22

i feel good...

Answer 23

=D

Answer 24

o ok thank u

Answer 25

lol, a song just hit me when you said that.

Answer 26

it's a pleasure flash ^_^ good luck!

Answer 27

are you saying that you are feeling good andy? or are you singing? ^_^

Answer 28

-30x^2y^2-12xy^2

Answer 29

both

Answer 30

*dancing* *singing* *happy*

Answer 31

my papper is due n 7 min can u giveme the anwsers

Answer 32

One factor is 6

Answer 33

What additional factors can you extract from the two terms
\[6___(-5x ^{2}y ^{2}-2xy ^{2})\]

Answer 34

lol andy, you deserve to be so, we all do :)

Answer 35

6xy^2(-5x-2)

Answer 36

thank u 5cx^2+10c^2x-15c^3

Answer 37

angoo, now to come to think of it, you're doing 3 things and not 2 LOL =D

Answer 38

5c(x^2+2cx-3c^2)

Answer 39

If you wait this long to do your work, you need to change that handle Flash!lol

Answer 40

awsome 36a^2b^3c^2-48ab^4c^3+60a^3b^2c

Answer 41

12ab^2c(3abc-4b^2c^2+5a^2)

Answer 42

thank u 35m^6n^3-49m^3n^4+7m^3n^4

Answer 43

7m^3n^3(5m^3-7n+n)

Answer 44

Sorry but I got to go to insurance office.

Answer 45

awsome 33x^2y^4z+55xy^2z^5=66x^6yz^3

Answer 46

Good luck....will take one more if you have any more. I hope you are reviewing the answers.

Answer 47

33x^2y^4z+55xy^2z^5=66x^6yz^3

Answer 48

11xyz(3xy^3+5yz^4-6x^5z^2)

Good luck and catch you later.