Question

need help with stating excluded values for a rational expression. m^2-1 over 2m^2-m-1

Answer 1

I have a similar problem, this stuff seems fishy, but I know it must be simple

Answer 2

can you figure this out?

Answer 3

if we factor the top and bottom, we can determine the "excluded" values...

Answer 4

m^2-1 factors to:

(m-1)(m+1) its called the difference of squares

2m^2-m-1 factors to:

(2m-3)(m+1)

so we have:

(m-1)(m+1)
----------- anything that makes the bottom a "zero" is excluded
(2m-3)(m+1)

m=3/2 and m=-1 should be illegal to use..

at m=3/2 we have a vertical asymptote; and at m=-1 we have a "hole" in the graph.