Question

4e^(x-1)=64

Answer 1

x=(ln16)+1

Answer 2

How did you get that?

Answer 3

e^(x-1)=16 then you ln both side
-> x-1=ln16 x=(ln16) +1

Answer 4

ummmmmmm yeah still not getting it.

Answer 5

What you mean?

Answer 6

like for instance where did the ln come from and why is it hooking up with the 16. Then why are you replacing x with ln16?

Answer 7

e^(x-1) =64/4 Then you take the natural log(or ln) of both side,
because ln(e^x)=x which is an identity, so you got x-1= ln 16 then you solve for x by adding 1 to both side

Answer 8

http://en.wikipedia.org/wiki/Natural_logarithm you can check this out if you dont know the identity

Answer 9

okay thank you for your help its highly appreciated!! :0]

Answer 10

:)

Answer 11

divide both sides by 4
you are left with....e^x-1=16......then introduce the natural log on both sides