Question

how do you solve (-3-4x)^1/2-(-2-2x)^1/2=1

Answer 1

alright, if I'm not wrong , you'll have to multiply the left side with
\[\sqrt{-3-4x} +\sqrt{-2-2x}\] up and down , then you'll get :
\[(-3x-4x) -(-2-2x) = 1\]

simply subtract and solve for x and you'll get :
\[-3-4x +2 +2x -1 = 0\]
-2x -1 -1 = 0
-2x = 2
x = -1

Correct me if I'm wrong ^_^

Answer 2

oh thank you so much thank you =)
i was really having a hard time with this

Answer 3

and i will

Answer 4

yeah i think your right

Answer 5

you're welcome ^_^ good luck!