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Mathematics 7 Online
OpenStudy (anonymous):

(2x2 - 4x – 5) + (10x2 + 3x)

OpenStudy (anonymous):

12x^2-x-5, solve for x using x = -b +or - (sqrt(b2-4ac)/2a)

OpenStudy (anonymous):

i dont understand

OpenStudy (anonymous):

is the equation \[(2x ^{2}-4x-5) + 10x ^{2}+3x\] ?

OpenStudy (anonymous):

yes its subtracting polynomials

OpenStudy (anonymous):

then it becomes: \[2x ^{2}+10x ^{2}-4x+3x-5 \rightarrow \rightarrow 12x ^{2}-x-5\]

OpenStudy (anonymous):

you are basically bunching up all the x^2 terms together, all the x terms together and all the constants together. If you are asked to solve this equation for x, then you can solve it using the formula i gave above for quadratic equations, but if you are not asked to solve for x, don't worry about it just yet.

OpenStudy (anonymous):

lol what he's trying to say is, let's expand it and you'll get :\[= 2x^2-4x-5 +10x^2 + 3x\] let's add, and we'll get : \[= 12x^2-x-5\] done ^_^ , understand it now? :)

OpenStudy (anonymous):

lol, thats exactly it. sorry, my maths is a bit rusty. it's all kind of obvious to me.

OpenStudy (anonymous):

haha its ok but thank you

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