(2x2 - 4x – 5) + (10x2 + 3x)
12x^2-x-5, solve for x using x = -b +or - (sqrt(b2-4ac)/2a)
i dont understand
is the equation \[(2x ^{2}-4x-5) + 10x ^{2}+3x\] ?
yes its subtracting polynomials
then it becomes: \[2x ^{2}+10x ^{2}-4x+3x-5 \rightarrow \rightarrow 12x ^{2}-x-5\]
you are basically bunching up all the x^2 terms together, all the x terms together and all the constants together. If you are asked to solve this equation for x, then you can solve it using the formula i gave above for quadratic equations, but if you are not asked to solve for x, don't worry about it just yet.
lol what he's trying to say is, let's expand it and you'll get :\[= 2x^2-4x-5 +10x^2 + 3x\] let's add, and we'll get : \[= 12x^2-x-5\] done ^_^ , understand it now? :)
lol, thats exactly it. sorry, my maths is a bit rusty. it's all kind of obvious to me.
haha its ok but thank you
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