I really need help. I am 50 yrs old, and these math problems are killing me. If I do not pass, I do not graduate. I am looking for help with base ten/base five/ base two/ ect. type problems including binary as well. 1st problem is 79 base two.

Question

I really need help.  I am 50 yrs old, and these math problems are killing me.  If I do not pass, I do not graduate.  I am looking for help with base ten/base five/ base two/ ect. type problems including binary as well.  1st problem is 79 base two.

anonymous · Answer

hhahah

nikvist · Answer

79:2=39|1
39:2=19|1
19:2=9|1
9:2=4|1
4:2=2|0
2:2=1|0
1:2=0|1
$$79_{10}=1001111_2$$

anonymous · Answer

79 in binary (base 2) is 1001111.  The base is how many numbers there are per character (ie base ten has 0-9 which is ten, base 2 has 0-1 which is two)  in binary each slot means a different ammount. first 1, then 2 then 4 then 16 and so on (eash slot is *2 of the previous slot)  so for your 79 example that means theres a 1, a 2, a 4, a 8, no 16, no 32, and a 64. note that 1+2+4+8+0+0+64=79

amistre64 · Answer

79 in uninary is:

 1111111111111111111111111111111111111111111111111111111111111111111111111111111

anonymous · Answer

for base five you would have 1,2,3,4 then 10 would be 5. 11 would be 6, 12 would be 7 and so on

anonymous · Answer

google this stuff up, and there you will find some articles how to do it
also, I would recomend you to ask someone from the place you are about to graduate at to help you out. Just dont be afraid to ask.