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Find the extreme point(s) of the function f(x) = 0.25x^4+3x^3-18x^2+10 and classify them.
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1 - Differentiate f(x) 2 - Solve f'(x)=0 3 - Use sign diagram or 2nd derivative for classification of the extreme points ---I'll do 1 and 2 for you... --- 1: f'(x)=x^3+9x^2-36x 2: Solution by factorization: x(x^2+9x-36)=0 , x(x+12)(x-3)=0 solutions: x=0, x=-12, x=3 3: f''(x)=3x^2+18x-36 f''(0)=-36<0 -> Local max at x=0 Point (0,10) f''(-12) (saved as exercise ;-) ... f''(3)...
Thanks for your help. I will finish it.
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