Question

ok so i need help finding the perimeter, the hight,the surface aria, and the slant hight of a square pyramid..who can help

Answer 1

Pythagoras probably could have helped :(

Answer 2

what

Answer 3

http://en.wikipedia.org/wiki/Pythagorean_theorem

Answer 4

well i got that...i just have a limited about of numbers that help me at all

Answer 5

i have a volume that =340 and values of x1-12 that equal the base lengths

Answer 6

Is it a regular square based pyramid (i.e. the 4 triangles are equilateral)? If so, then that is probably enough. If not, you're f*cked

Answer 7

umm...thanks

Answer 8

I was trying to help. No need to get all dorky on me.

Answer 9

lol...i am a dork to begin with...so im sorry but you are going to have to retard this out for me

Answer 10

Have fun.

Answer 11

not helping..im having issues trying to figure out what goes in the calculator

Answer 12

What is x1? just a random number?

Answer 13

ok so i got the perimeter which is \[p=x \times 4 \]

Answer 14

now i need to get the side length which is \[a^2+b^2=c^2 so what is a b and c\]

Answer 15

OK I will try and do this quickly - what EXACTLY do you know?

Answer 16

i know the volume is 340 inches cubed..and that 1 is the side length

Answer 17

Do you mean 1 is the length of the 4 edges of the base? Or the length of the slants?

Answer 18

oops yes that is what i ment

Answer 19

Well if that is the case, the volume = 340 = (1/3) * 1^2 * height , so height = 1020... which sounds retardedly big.

But if that was right, the slant length ^2 = 1^2 + 1020^2

And surface area = 2 * slant length * base length + base length squared


Weird question, but I have to bye. bye babe xx