Question

Proving the following trig identities:
sin^2 (x/2)= (csc x - cot x)/ (2 csc x)
help please

Answer 1

i get that (1-cosx)/2 = (csc x - cot x)/ (2 csc x) does it help ?

Answer 2

you need to find the relation between (1-cosx)/2 and sin^2 (x/2)=

Answer 3

thank you for explaining, this helps a lot :)

Answer 4

you didn't forgot any square in sin^2 (x/2)= (csc x - cot x)/ (2 csc x)
?

Answer 5

thank you i proved it with your help :)

Answer 6

how did you do it :o ?

Answer 7

The LHS is just (1/2) (1+ cos(x)), so it becomes cos(2a) = 1 - sin^2(a) (standard)

with a = x/2

Answer 8

1-cos(x) *** My bad

Answer 9

I still don't get the last part :(