Question

how would you simplify (6n/n+1)divided by (6n/n^2 +5n+4)

Answer 1

Alright, let's re-write it in a better form and you know that when we divide my a fraction, it's like we're multiplying the reciprocal of it so we'll get :
\[(6n)/(n+1)\] multiplied by
\[(n^2+5n+4)/(6n)\]
so now we can cancel the 6n with the 6n and we'll be left with:

\[(n^2+5n+4)/(n+1)\]
now let's factor the top :
\[(n+1)(n+4)/(n+1)\]
and let's cancel the n+1 from top and bottom:
\[n+4\]

so n +4 is your final simplified answer ^_^ hope it's clear now

Answer 2

by a fraction* ^^"