Question

a dice is thrown four times. what is the probability that it we will get the same number at last twice???

Answer 1

Count the possibilities, to get those results, without counting anything more than once. e.g. there are 6 results where all three are the same. Then divide that number by the number of all possible outcomes (which is 6^3)

Answer 2

I do not understand ur reasoning?

Answer 3

It is an Laplace experiment. So in order to get the probability you have to divide the number of positive outcomes by the number of all outcomes.

Answer 4

but when you throw the dice once, you have the probability 1/6 that it is 5 for example
but here the dice is thrown 4 times?

Answer 5

do i have to multiply the probabilities?

Answer 6

or is it conditional probability p(A/b)

Answer 7

no, you should take every quadruple-combination as a single outcome.

Answer 8

so in total there are 6^4 results I think?

Answer 9

now how do i find the rest?

Answer 10

yes, true

Answer 11

There are certainly several ways to count. I would count the disjount situations 1 Pair; 2 Pairs and 1 Tripel seperately. Use binomial to see which of the dices are equal and then multiply with the possible count of numbers.

Answer 12

is it 66/6^4

Answer 13

yes, thats what i did and i think there were 66?

Answer 14

toooooo complicated, nyway thank you

Answer 15

Well I get 6*6*5*4+4*6*5+6*6*5 = 1020 which makes about .787

Answer 16

not sure......

Answer 17

ah ok, I really made it too complicated
you should look at the complementary event: "all 4 numbers are different"

Answer 18

there you can count easily 6*5*4*3 = 360

Answer 19

ah, got it now, thats easier

Answer 20

so the answer must b 6*5*4/6^4

Answer 21

now yes!
thanx