Question

anyone know logs?

log(d)+log(2d+1)=log(7d)

Answer 1

logx+logy=log(xy) so you can use that property here

Answer 2

so it becomes log(d(2d+1))=log(7d) ? what then

Answer 3

So you are almost there. Multiply the d through the quantity (2d+1) and according to the property you can set that value equal to 7d and solve for d.

Answer 4

so log2d^2+d=log7d can just become 2d^2+d=7d?

Answer 5

that's correct, now solve for d.

Answer 6

ok thanks :) I never liked logs