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How do you factor x^3-6x^2+11x-6=0?
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Are you trying to find the real roots?
Yes, the solution is (x-1)(x-2)(x-3), I don't know how to get that
possible roots will be the factors of 6(or the constant in general) which are +/-1 +/-2 +/-3 +/-6
So, do you just plug those in and see what works?
yea
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this is the only way i know ..hope it help
Thats helps, thank you!
dichalao's hint regarding the factors of the constant, 6 in this case, is presented at: http://www.purplemath.com/modules/rtnlroot.htm A quality plotting program can also be a great help. Refer to the attachment.
Thank you~!
My pleasure.
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