Question

5y(-y^2-7y)

Answer 1

\[5y(-2y ^{2}-7y)\]

Answer 2

so what do you know to do to this problem?

Answer 3

i dont know how to do these types of problems im home sick today and this is the practice problems the teacher wants me to do to turn in tomorow to see if i need to do the assighnment or not

Answer 4

ok... lets review some basic concepts then ok.

Answer 5

to make it easier, lets do this:

3(8) = 24 right?

Answer 6

yeah

Answer 7

then this should also equal 24:

3(6+2) = 24 ...make sense?

Answer 8

yeah

Answer 9

good, now how do we prove this? we "distibute" that 3 thru the (6+2) like this, just multiply it thru...

3(6) + 3(2) = 24

18 + 6 = 24

24 = 24....

Do you see how I did that?

Answer 10

distribute is the word I was trying to type :)

Answer 11

yeah so if i do that for this problem i end up with -45y^{2} would that be correct

Answer 12

-45y squared

Answer 13

not yet, there are a few more things to iron out...

Answer 14

you see the "y"'s in there....they play by the same rules, but with a difference result

Answer 15

so it would be just -45?

Answer 16

quit trying to jump ahead of the curve, if you simply want ananswer to it it aint gonna be useful to you..... we will get to the answer soon enough :)

Answer 17

do you know how the rules of positive and negatives work with multiplication?

(+)(+) = (+)

(-)(-)=(+)

(-)(+)=(-)

do you know these rules?

Answer 18

yes

Answer 19

good, then the only thing left to do is to figure out what to do with they "y"s :)

Answer 20

y^2 means that you have 2 little y's that have been pushed together like this:

yy = y^2

y^5 means 5 little y's are pushed together like this:

yyyyy = y^5

does that make sense?

Answer 21

yeah

Answer 22

good, when we multiply these y's together, we simply add up all the little y's together, for example:

y^2 times y^5 = yy yyyyy = yyyyyyy = y^7

y^1 times y^3 means y yyy = yyyy = y^4

does that make sense?

Answer 23

yea

Answer 24

then lets step thru your problem and use this understanding to get the answer :) ok?

Answer 25

ok

Answer 26

5y(-y^2-7y) lets distribute that 5 thru to get:

5(-y^2) + 5(-7y) = (-10y^2 -35y)

now were left with that y on the outside to distribute thru like this:

y(-10y^2 -35y)

y(-10y^2) + y(-35y)

-10yyy + -35yy = -10y^3 -35y^2 and thats as far as we can take it

Answer 27

and I messed it up lol.....

Answer 28

5(-y^2) = -5y^2...

Answer 29

copy edit repaste...

Answer 30

5y(-y^2-7y) lets distribute that 5 thru to get:

5(-y^2) + 5(-7y) = (-5y^2 -35y)

now were left with that y on the outside to distribute thru like this:

y(-5y^2 -35y)

y(-5y^2) + y(-35y)

-5yyy + -35yy = -5y^3 -35y^2 and thats as far as we can take it

Answer 31

so then the answer would be -5y^3-35y^2?

Answer 32

yep, thats the answer

Answer 33

oh ok thanks

Answer 34

youre welcome