Question

how do you solve these problems: 2n(squared) - 11n + 15 and
-3n(squared) - 75

Answer 1

are you dealing with imaginary numbers?

Answer 2

no i am dealing with factoring polynomials

Answer 3

so 2n^2-11n+15 = 2n^2 -6n-5n+15

Answer 4

thank you so much!!

Answer 5

-3n^2-75=0--------> n^2=-25

Answer 6

thank you soo much!!

Answer 7

you are welcome. note that for the second equation, you will have imaginary roots.

Answer 8

Since we are tasked to factor the polynomials, take a close look at the second equation.\[-3n ^{2}-75\]

Answer 9

It is a factor problem, extract the -3 which is present in both terms.\[-3(n ^{2}+25)\]

Answer 10

Thats is about as far as you can go with this.

Answer 11

That's true, unless the right hand side is specified in the equation.

Answer 12

I didn't notice any but if it is zero, we would have the situation that you mentioned and probably doehrman hasn't got into complex number yet.

Answer 13

yes, you are right