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Anyone want to help me with integral of (x^2-1)/x from 1 to 2?
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I know it equals 3/2 -ln(2), but cant get the 3/2 part, i get -1/2
So I assume you did the integration correct since it looks like the form of your answer is right. I think you made a mistake when evaluating from 1 to 2.
I just figured it out...It didnt register for me that x^2/x can be x...duhhh ahha, so I computed x^2(x^-1)
Ok...got it though correct?
ahhh, i just really messed it up because then I put x^-1/1, instead of over -1
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yeah got it now thanks
Didn't do anything, it was all you. But no problem :)
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