Question

i don't understand what to do here:
Find ds/dt when θ=π if s=cosθ and dθ/dt=-6...

Answer 1

Message was truncated. Retry the question.

Answer 2

given
\[s=\cos\theta\]
so, we can say
\[\frac{ds}{dt}=-\sin\theta \frac{d\theta}{dt}\]
also given that
\[\theta = \pi, \frac{d\theta}{dt}=-6\]
so we get
\[\frac{ds}{dt}=-\sin\theta \frac{d\theta}{dt}=0\]