Question

80=1/9x^2+11/3x

solve for x

Answer 1

Do you mean \[80=\frac{1}{9}x^2+\frac{11}{3}x\]?

Answer 2

If so, multiply everything through by the highest denominator to eliminate your fractions. Here, multiply through by 9 to get\[720=x^2+33x\]

Answer 3

This is quadratic, so you have\[x^2+33x-720=0\] which can be factored into \[(x-15)(x+48)=0\]

Answer 4

For this to be true, either one, or both, of the factors have to be zero. Hence, your x-values are\[x=15,x=-48\]

Answer 5

thank you!

Answer 6

np